SOLUTION: The height , h, in feet, of a bottle rocket is modeled by: h = -16t^2 +60t where t is the time in seconds. A. Factor the expression. H = -16t^2 + 60t = 4t (-4t +

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: The height , h, in feet, of a bottle rocket is modeled by: h = -16t^2 +60t where t is the time in seconds. A. Factor the expression. H = -16t^2 + 60t = 4t (-4t +      Log On

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Question 1085745: The height , h, in feet, of a bottle rocket is modeled by: h = -16t^2 +60t

where t is the time in seconds.
A. Factor the expression.
H = -16t^2 + 60t = 4t (-4t + 15)
B. What is the height of the rocket after 2 seconds?
When t = 2
H = 4t(-4 times 2 + 15) = 28
C. What is the height of the rocket after 3.75 seconds? Explain the solution.
When t = 3.75
H = 4t(-4 times 3.75 + 15) = 0
The Bottle Rocket should have landed after 3.75 seconds.



Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

h+=+-16t%5E2+%2B60t where t is the time in seconds.
A. Factor the expression.
H+=+-16t%5E2+%2B+60t+=+4t+%28-4t+%2B+15%29
B. What is the height of the rocket after 2 seconds?
When t+=+2
H+=+4%2A2%28-4%2A2+%2B+15%29+=+8%28-8%2B15%29=8%287%29=56
C. What is the height of the rocket after 3.75 seconds? Explain the solution.
When t+=+3.75
H+=+4%2A3.75%28-4+%2A+3.75+%2B+15%29+=15%28-15%2B15%29=15%2A0+=0
The Bottle Rocket should have landed after 3.75+seconds.