SOLUTION: A diplomat travels from point X to Y. If he will be departing X at 8:00 AM, and travel 2 kilometers per hour, he will arrive at Y, 3 minutes earlier than his expected time of arriv

Let D be the unknown distance from X to Y.

Moving at 2 km/h, the diplomat will spend  hours.

Moving at 3 km/h, the diplomat will spend  hours.

The condition says 

 = 30 minutes + (6-3) minutes = 33 minutes.    (It is the "time difference" equation)

         Try to understand on your own how these numbers come from the condition 
         and how and why do they combine in this expression (30 + (6-3)) minutes.


But we need to write both sides of the last equation in uniform units. So, this equation will take the form

 =  of an hour.


To solve this equation, multiply both sides by 60. You will get

30D - 20D = 33  ---->  10D = 33  ---->  D =  = 3.3 kilometers.

Thus we found the distance. It is 3.3 kilometers.

Now, at the second scenario, the diplomat starts at 8:30 am,  moves  = 1.1 hour = 1 hour 6 minutes and arrives at 9:36 am, 
which is 6 minutes late.

Hence, the meeting is scheduled at 9:30 am.