SOLUTION: A piece of copper 4 inches in length, 2 in. in width, and 1/2 in. thick is formed into a wire of uniform thickness and 100 yds. in length. Determine diameter of wire. Solution

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: A piece of copper 4 inches in length, 2 in. in width, and 1/2 in. thick is formed into a wire of uniform thickness and 100 yds. in length. Determine diameter of wire. Solution       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1081380: A piece of copper 4 inches in length, 2 in. in width, and 1/2 in. thick is formed into a wire of uniform thickness and 100 yds. in length. Determine diameter of wire.
Solution with problem:
Let d = diameter.
4 * 2 * 1/2 = 4 cu. in. (Volume of copper).
100 * 3 * 12 = 3600 in. (Length of wire).
pi / 4 * d^2 * 3600 = 4 **
d^2 = 4 * 4 / pi * 3600 = 1 / 225 * pi **
d = 0.376 in.

** I don't understand these steps. Non-homework. Thanks.

Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
You most likely want diameter of the wire in inches. Volume of the initial copper piece will be equal to the volume of the resulting wire.

36 inches is 1 yard.

d, for the DIAMETER, in inches;
All length or distances are used in their inches units;
4%2A2%2A%281%2F2%29%2Ainch%2Ainch%2Ainch=100%2A36%2Api%2A%28d%2F2%29%5E2%2Ainch%5E3
d is for diameter, in inches.

If you can understand that equation then the steps for solving d should be clear, uncomplicated.

4=3600%2Api%2A%281%2F4%29d%5E2

d%5E2%2Api%2A%283600%2F4%29=4

d%5E2=4%284%2F3600%29%281%2Fpi%29

d=%284%2F60%29%281%2Fsqrt%28pi%29%29

d=%281%2F15%29%281%2Fsqrt%28pi%29%29

d=1%2F%2815%2Asqrt%283.14159%29%29

highlight%28d=0.0376%29, inches