SOLUTION: On a day when the weather bureau announced that the wind was blowing at 5 km/h Scott's radio-controlled airplane flew a measured course in 1 min 48 s with the wind, and in 3 min ag
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Question 1046368: On a day when the weather bureau announced that the wind was blowing at 5 km/h Scott's radio-controlled airplane flew a measured course in 1 min 48 s with the wind, and in 3 min against the wind. What was the length of the course?What was the rate of the plane in still air?
please help me with this question.
Thank you very much.
48 seconds is 48/60ths of a minute which is to say 8/10ths of a minute. Hence the "with the wind" leg took 1.8 minutes. Since the wind speed is given in km/hr, we convert the elapsed time to hours. 1.8 divided by 60 is 0.03 hours and 3 divided by 60 is 0.05 hours. Distance equals rate times time. Let km/hr be the speed of the plane. The total rate with the wind is the sum of the plane's speed and the wind speed. The rate against the wind is the difference, so:
But since
Solve for , then calculate . Then check your work by calculating and make sure the distances are the same.
John
My calculator said it, I believe it, that settles it
