SOLUTION: Hi 2 bottles x and y contain water.from bottle x we pour into bottle y twice as much water as y already contains.we then pour from y into x as much water as x now contains. Both b

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Hi 2 bottles x and y contain water.from bottle x we pour into bottle y twice as much water as y already contains.we then pour from y into x as much water as x now contains. Both b      Log On

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Question 1043772: Hi
2 bottles x and y contain water.from bottle x we pour into bottle y twice as much water as y already contains.we then pour from y into x as much water as x now contains. Both bottles now contain 200ml.how much water was in each bottle initially.
thank you

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = ml of water in x bottle initially
Let +y+ = ml of water in y bottle initially
-----------------------------------
(1)
After 1st step:
Bottle x has: +x+-+2y+ ml
Bottle y has: +y+%2B+2y+ ml
-------------------------
(2)
After 2nd step:
Bottle x has: +%28+x+-+2y+%29+%2B+%28+x+-+2y+%29+
Bottle y has: +%28+y+%2B+2y+%29+-+%28+x+-+2y+%29+
-----------------------------------
I am given that
+%28+x+-+2y+%29+%2B+%28+x+-+2y+%29+=+200+
+%28+y+%2B+2y+%29+-+%28+x+-+2y+%29+=+200+
----------------------------
(1) +2x+-+4y+=+200+
(2) +-x+%2B+5y+=+200+
-----------------------
Multiply both sides of (2) by +2+
(1) +2x+-+4y+=+200+
(2) +-2x+%2B+10y+=+400+
----------------------
+6y+=+600+
+y+=+100+
---------------
If both bottle end up with 200 ml, there has to
be 400 ml total, so
+400+-+y+=+x+
+400+-+100+=+x+
+x+=+300+
--------------------
Initially, x has 300 ml
y has 100 ml
------------------------
check answer:
(1)
After 1st step:
Bottle x has: +x+-+2y+=+300+-+2%2A100+
+300+-+200+=+100+ ml
Bottle y has: +y+%2B+2y+=+100+%2B+2%2A100+
+100+%2B+200+=+300+ ml
--------------------------------
(2)
After 2nd step:
Bottle x has: +%28+x+-+2y+%29+%2B+%28+x+-+2y+%29+=+%28+325+-+2%2A75+%29+%2B+%28+325+-+2%2A75%29+
+300+-+200+%2B+300+-+200+=+600+-+400+
+600+-+400+=+200+ ml
Bottle y has: +%28+y+%2B+2y+%29+-+%28+x+-+2y+%29+=+3%2A100+-+300+%2B+2%2A100+
+300+-+300+%2B+200+=+200+ ml
----------
Both bottles end up with 200 ml
OK