SOLUTION: A boy saves Re. 1 on the first day of the month, Rs. 2 on the 2nd day, and so on upto 12 days. How much does he save? a. Rs. 4095 b. Rs. 36 c. Rs. 512 d. Can’t be determined

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Question 1039342: A boy saves Re. 1 on the first day of the month, Rs. 2 on the 2nd day, and so on upto 12 days. How much does he save?
a. Rs. 4095 b. Rs. 36 c. Rs. 512 d. Can’t be determined

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
My guess is that the expected answer is "a. RS. 4095",
but this problem (as stated) is ambiguous, because "and so on" can be interpreted two ways.
Does he save each day Rs. 1 more than the day before?
Or does he save each day twice as much as the day before?
Or is the wording purposefully ambiguous?

In life (and school) sometimes you have to answer the expected answer, even if it is not the correct answer to the question asked.
Sometimes you have to lie.
Sometimes you have to figure out what was the question that was meant to be asked, and answer the question meant, instead of what was asked.

The answer to the problem as stated, is d.
However, was the problem meant to be ambiguous? If so d. is the expected answer.
Or was the question meant not exactly the one you posted?

INTERPRETATION # 1:
It is a trick question, meant to be ambiguous, and d. is the expected/correct answer.

INTERPRETATION # 2:
The question meant could state that
"A boy saves Rs. 1 the first day, Rs. 2 the second day, Rs. 3 the third day, and so on for 12 days."
The boy saves each day Rs. 1 more than the day before.
The savings form an arithmetic sequence, with
first term = a%5B1%5D=%22Rs.%221 , and
common difference = d=%22Rs.%221 .
In that case,
last term = a%5B12%5D=a%5B1%5D%2B%2812-1%29%2Ad=%22Rs.+1%22%2B11%2A%22Rs.+1%22=%22Rs.+12%22
and the sum of the 12 terms is
.
Since that is not one of the choices given for the answer, that is probably not the right interpretation.

INTERPRETATION # 3:
The question meant could state that
"A boy saves Rs. 1 the first day, Rs. 2 the second day, Rs. 4 the third day, and so on for 12 days."
The boy saves each day twice as much as the day before.
The savings form a geometric sequence, with
first term = b%5B1%5D=%22Rs.%221 , and
common ratio = r=2 .
In that case,
the n%5Eth term is b%5Bn%5D=b%5B1%5D%2Ar%5E%28n-1%29 ,
and the sum of the first n terms is
S%5Bn%5D=b%5B1%5D%28r%5En-1%29%2F%28r-1%29 .
THat would make the answer
.