SOLUTION: Hi
Betty has 1/3 as many pins as susan.when susan gave away 55 pins, the number of pins Betty has is twice the number susan has left..how many pins does susan have at first.
th
Algebra ->
Customizable Word Problem Solvers
-> Misc
-> SOLUTION: Hi
Betty has 1/3 as many pins as susan.when susan gave away 55 pins, the number of pins Betty has is twice the number susan has left..how many pins does susan have at first.
th
Log On
Question 1038579: Hi
Betty has 1/3 as many pins as susan.when susan gave away 55 pins, the number of pins Betty has is twice the number susan has left..how many pins does susan have at first.
thanks Answer by jorel555(1290) (Show Source):
You can put this solution on YOUR website! Let s be susan, b be betty. Then:
s=3b
s-55=b/2. So:
3b-55=b/2
6b-110=b
5b=110
b=22
s=66
Betty has 22 pins to start, Susan has 66!!!!!!!!!!!!!!
(