SOLUTION: The Home Depot recently sold 23 watt CFL bulbs for $250 each and 42 watt CFL bulbs for $8.25. If River Memorial Hospital purchased 200 such bulbs for a total of $1305, how many of

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: The Home Depot recently sold 23 watt CFL bulbs for $250 each and 42 watt CFL bulbs for $8.25. If River Memorial Hospital purchased 200 such bulbs for a total of $1305, how many of       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1034478: The Home Depot recently sold 23 watt CFL bulbs for $250 each and 42 watt CFL bulbs for $8.25. If River Memorial Hospital purchased 200 such bulbs for a total of $1305, how many of each type did they purchase?
Found 3 solutions by josgarithmetic, ikleyn, robertb:
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
The is the same type of problem as the very common Ticket Sales type. A system of two linear equations in two unknown variables. Account for how many bulbs and account for the cost of the bulbs.

Answer by ikleyn(52788) About Me  (Show Source):
You can put this solution on YOUR website!
.
The Home Depot recently sold 23 watt CFL bulbs for $250 each and 42 watt CFL bulbs for $8.25.
If River Memorial Hospital purchased 200 such bulbs for a total of $1305, how many of each type did they purchase?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

". . . 23 watt CFL bulbs for $250 each"

For how many each?


Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
I will make the assumption that you actually meant a 23-watt CFL bulb to be $2.50 each. It doesn't make sense that each one costs $250.
Let x = number of 23-watt CFL bulbs purchased,
y = number of 42-watt CFL bulbs purchased.
With this in mind,you can come up with the system
2.50x + 8.25y = 1305,and
x + y = 200
Using Cramer's rule,
,and
.
Therefore 60 23-watt CFL bulbs were purchased, and 140 42-watt CFL bulbs purchased.