Question 1031871: Ok people, let's have some fun with algebra! See if you can solve this fun question.
There are 65 people on an airplane. Out of those 65 people there are three times as many women as there are men, ten less girls than there are women and the amount of boys is only a quarter of the amount of girls.
How many men, women, girls and boys are on board the plane?
Have fun!
Found 2 solutions by stanbon, MathTherapy:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! There are 65 people on an airplane. Out of those 65 people there are three times as many women as there are men, ten less girls than there are women and the amount of boys is only a quarter of the amount of girls.
How many men, women, girls and boys are on board the plane?
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w = 3m
g = w-10
b = (1/4)g
w + m + g + b = 65
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Get it down to one variable:
m = (w/3)
g = w - 10
b = (1/4)g = (1/4)(w-10) = (w-10)/4
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Substitute to get:
w + (w/3) + w-10 + (w/4) - (10/4) = 65
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12w + 4w + 12w - 120 + 3w - 30 = 65*12
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31w = 930
w = 30 (# of women)
m = (w/3) = 10 (# of men)
g = w-10 = 20 (# of women)
b = (1/4)g = 5 (# of women)
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Cheers,
Stan H.
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Answer by MathTherapy(10551)  (Show Source):
You can put this solution on YOUR website!
Ok people, let's have some fun with algebra! See if you can solve this fun question.
There are 65 people on an airplane. Out of those 65 people there are three times as many women as there are men, ten less girls than there are women and the amount of boys is only a quarter of the amount of girls.
How many men, women, girls and boys are on board the plane?
Have fun!
Let number of men be M
Then number of women = 3M
Number of girls: 3M - 10
Number of boys: 
Thus, 
Solve for M, the number of men, and then the other numbers. Is this supposed to be a challenge?
If it was supposed to be, then I must've misunderstood something!
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