SOLUTION: Please help me understand how to solve these word problems. Not just get the answers but a better understanding.
Working together, Aaron and Rosa can mow the lawn around the loc
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Working together, Aaron and Rosa can mow the lawn around the loc
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Question 1030790: Please help me understand how to solve these word problems. Not just get the answers but a better understanding.
Working together, Aaron and Rosa can mow the lawn around the local library in 3 hours. Working alone Aaron can mow the lawn in 5 hours. Write and solve an equation to determine how long it would take Rosa to mow by herself. Found 4 solutions by mananth, rothauserc, ikleyn, MathTherapy:Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! Working together, Aaron and Rosa can mow the lawn around the local library in 3 hours. Working alone Aaron can mow the lawn in 5 hours. Write and solve an equation to determine how long it would take Rosa to mow by herself.
Working alone Aaron can mow the lawn in 5 hours
Aaron does 1/5 of the job in 1 hour
Working alone rosa can mow the lawn in x hours
Rosa does 1/x of the job in 1 hour
Working together, Aaron and Rosa can mow the lawn around the local library in 3 hours.
They do 1/3 of the job in 1 hour
1/5 + 1/x = 1/3
1/x = 1/3 -1/5
1/x = 2/5
x= 5/2
Working alone Aaron can mow the lawn in 2 hours 30 minutes
You can put this solution on YOUR website! Aaron mows the lawn in 5 hours, so he does 1/5 of the job per hour. Let x be the number of hours Rosa takes to mow the lawn, then
:
1/5 + 1/x = 1/3
:
multiply both sides of the = by 15x
:
3x + 15 = 5x
:
2x = 15
:
x = 7.5
:
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It takes Rosa 7 1/2 hours to mow the lawn
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:
You can put this solution on YOUR website!
Please help me understand how to solve these word problems. Not just get the answers but a better understanding.
Working together, Aaron and Rosa can mow the lawn around the local library in 3 hours. Working alone Aaron can mow the lawn in 5 hours. Write and solve an equation to determine how long it would take Rosa to mow by herself.