SOLUTION: A Turtle and a Snail are 360 meters apart, and they start to move towards each other at 3 p.m. If the Turtle is 11 times as fast as the Snail, and they met at 3:40 p.m., find the s

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Question 1028963: A Turtle and a Snail are 360 meters apart, and they start to move towards each other at 3 p.m. If the Turtle is 11 times as fast as the Snail, and they met at 3:40 p.m., find the speed of each.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
You can think of this as one of them standing still
and the other moving at the sum of their speeds
3:40 minus 3:00 is 40 min
Convert to hrs:
+%2840%2F60%29+=+2%2F3+ hrs
Let +s+ = the speed of the snail
+11s+ = the speed of the turtle
------------------------------
+360+=+%28+s+%2B+11s+%29%2A%282%2F3%29+
+1080+=+24s+
+s+=+45+
and
+11s+=+11%2A45+
+11s+=+495+
----------------
The speed of the snail is 45 m/hr
The speed of the turtle is 495 m/hr
-----------------
check answer:
Equation for the snail:
+d%5B1%5D+=+45%2A%282%2F3%29+
+d%5B1%5D+=+30+
Equation for the turtle:
+d%5B2%5D+=+495%2A%282%2F3%29+
+d%5B2%5D+=+330+
----------------
+d%5B1%5D+%2B+d%5B2%5D+=+30+%2B+330+
++d%5B1%5D+%2B+d%5B2%5D+=+360+ m
OK