SOLUTION: It takes Earth approximately 365.2422 days to orbit the sun once, this is known as the tropical year and is the length of the cycle of seasons. In a regular year, there are 365 day

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Question 1023225: It takes Earth approximately 365.2422 days to orbit the sun once, this is known as the tropical year and is the length of the cycle of seasons. In a regular year, there are 365 days, and in a leap year there are 366 days. In a four-year period, one year being a leap year, what is the absolute difference between the number of days observed in the calendar years and the number of days in four tropical years? Express your answer as a decimal to the nearest ten-thousandth.
Thank you and please show all work to get you to the solution. Thanks

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The number of days in a period of four consecutive calendar years where one year is a leap year is the integer number
365%2A3%2B366=1461 ,
which we can express as 1461.0000 to the nearest ten-thousandth,
because 1%2F10000=0.0001 is one ten-thousandth.
The number of days in four orbits of Earth is the non-integer number
4%2A365.2422=1460.9688 .

The difference is
1461.0000-1460.9688=highlight%280.0312%29 .

NOTES:
1) The length of the tropical year changes a little over the centuries, but for now 365.24220 is a good approximation.
(I did not know that before your question, so thank you for the learning opportunity).
Since 365.24220 is a good approximation,
we do not have to worry about 365.2422 , given with 4 decimal places,
not being precise enough to make 1460.9688 not being 4%2A365.24220 to the nearest 1%2F1000 .

2) Calendar years are leap years if divisible by 4, but not by 100 unless divisible by 400 ,
so in 400 years there are 97 leap years,
and the average length of a calendar year is 365%2697%2F400=365.2425 .
(I was taught that in the 9th grade, and it stuck with me).