SOLUTION: Members of a boating club were assessed equally to raise $600 to pay for a new set of sails. When six more persons joined the club, the per member assessment was reduced by $5.00.

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Question 1011171: Members of a boating club were assessed equally to raise $600 to pay for a new set of sails. When six more persons joined the club, the per member assessment was reduced by $5.00. What was the new size of the club?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
p is for original number of club members.
Per-member rate was 600%2Fp dollars per member.

Six new members joined and this changes the per-member rate.
p+6 is the number of total members including the added five of them (new members).
Per-member rate now reduced by $5 each.
highlight_green%28600%2Fp-5=600%2F%28p%2B6%29%29
Do you understand the formation of this equation?

Solve for p, and then evaluate p+6.

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!
Members of a boating club were assessed equally to raise $600 to pay for a new set of sails. When six more persons joined the club, the per member assessment was reduced by $5.00. What was the new size of the club?
Let new size be M
Then original size = M - 6
Now, each member pays: 600%2FM%29, and originally, each member paid: 600%2F%28M+-+6%29
We then get the following equation, which describes the per-member payment, now and before: 600%2FM+=+600%2F%28M+-+6%29+-+5
600(M - 6) = 600M - 5M(M - 6) --------- Multiplying by LCD, M(M - 6)
600M+-+3600+=+600M+-+5M%5E2+%2B+30M
5M%5E2+-+600M+-+30M+%2B+600M+-+3600+=+0
5M%5E2+-+30M+-+3600+=+0
5%28M%5E2+-+6M+-+720%29+=+5%280%29
M%5E2+-+6M+-+720+=+0
(M - 30)(M + 24) = 0
M, or new size = highlight_green%2830%29 OR M = - 24 (ignore)