Lesson Minimize surface area of a conical paper cup with the given volume

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Minimize surface area of a conical paper cup with the given volume


Problem 1

A cone-shaped paper drinking cup is to hold  40 cm^3  of water.
Find the height and radius of the cup that will require the least amount of paper.

Solution

The volume of the cone cup is given 40 cm^3.


The lateral area of a cone is

    S = pi%2Ar%2As,       (1)

where r is the base radius and "s" is the slant height:  s = sqrt%28h%5E2+%2B+r%5E2%29.

So, we need minimize the lateral area

    S = pi%2Ar%2Asqrt%28h%5E2%2Br%5E2%29    (2)


at given restriction for the volume

    %281%2F3%29%2Api%2Ar%5E2%2Ah = 40  cm^3.    (3)


From the restriction (3),   

    h = 120%2F%28pi%2Ar%5E2%29. 


We substitute it into expression (2), and we get S(r) as a function of the radius r, only

    S(r) = pi%2Ar%2Asqrt%28%2814400%2F%28pi%5E2%2Ar%5E4%29%29+%2B+r%5E2%29 = sqrt%28%2814400%2Fr%5E2%29+%2B+pi%5E2%2Ar%5E4%29


    +-------------------------------------------------------+
    |    To find the minimum of S(r), we should calculate   |
    |         the derivative and equate it to zero.         |
    +-------------------------------------------------------+


I will not calculate the derivative in full, which is a complicated fraction. 
It is enough to calculate its numerator and equate it to zero. It gives this equation

    -2%2A%2814400%2Fr%5E3%29 + 4%2Api%5E2r%5E3 = 0,

or, equivalently

    7200 = pi%5E2%2Ar%5E6,   r%5E6 = 7200%2Fpi%5E2,   r = root%286%2C7200%2Fpi%5E2%29 = 3.0 cm.    (4)


So, the radius is just found.  The height should be  

    h = 120%2F%28pi%2Ar%5E2%29 = 120%2F%28pi%2A3%5E2%29 = 4.24 cm.    (5)


Expressions (4) and (5) give the required exact formulas and approximate numerical values.


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