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Finding the volume of a solid body mentally
Problem 1What is the volume of the solid in xyz-space bounded by surfaces y = x^2, y = 2 - x^2, z = 0 and z = y + 3?
Solution
I will show how to solve this problem mentally.
In (x,y)-plane, the area concluded between y = x^2, x-axis, and 0 <= x <= 1 is 1/3.
It is elementary calculation from Calculus.
From it, we deduce, that the area concluded between y = x^2, y = 1 and 0 <= x <= 1 is 2/3.
Hence, the area concluded between y = x^2 and y = 2-x^2 is 4 times 2/3, or 8/3 square units.
Now, our 3D solid consists of two parts.
One part is a right cylinder 0 <= z <= 3 over its base, which the area concluded
between y = x^2 and y = 2-x^2.
The volume of this cylinder is = 8 cubic units.
The other part is half of the cylinder 3 <= z <= 5 with the same base.
The height of this imaginary cylinder is 2 units (z from 3 to 5), so, its volume is = 16/3.
The plane z = z + 3 cuts this cylinder in two parts of equal volumes - it is clear from the symmetry.
So, the whole volume of the 3D body under the interest is = = = 32/3 cubic units.
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