Lesson Finding the volume of a solid body mentally

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Finding the volume of a solid body mentally


Problem 1

What is the volume of the solid in  xyz-space bounded by surfaces   y = x^2,  y = 2 - x^2,  z = 0  and  z = y + 3?

Solution

                    I will show how to solve this problem mentally.

In (x,y)-plane, the area concluded between y = x^2, x-axis, and 0 <= x <= 1 is 1/3.

It is elementary calculation from Calculus.


From it, we deduce, that the area concluded between y = x^2, y = 1  and 0 <= x <= 1 is 2/3.


Hence, the area concluded between y = x^2 and y = 2-x^2 is 4 times 2/3, or 8/3 square units.


Now, our 3D solid consists of two parts.


One part is a right cylinder 0 <= z <= 3 over its base, which the area concluded 
between y = x^2 and y = 2-x^2.


The volume of this cylinder is  %288%2F3%29%2A3 = 8 cubic units.



The other part is half of the cylinder  3 <= z <= 5  with the same base.

The height of this imaginary cylinder is 2 units (z from 3 to 5), so, its volume is %288%2F3%29%2A2 = 16/3.


The plane z = z + 3 cuts this cylinder in two parts of equal volumes - it is clear from the symmetry.


So, the whole volume of the 3D body under the interest is  8+%2B+16%2F6 = 8+%2B+8%2F3 = %2824%2B8%29%2F3 = 32/3 cubic units.


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