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Find the derivative for a function satisfying given functional equation
Problem 1
Find the derivative for function y = y(x), satisfying this functional equation = .
Solution
Starting equation is
x^3 + 2xy^2 = sin(y). (1)
Here x is an independent variable and y as a function of x
y = y(x).
Differentiate the given equation (1) (both sides separately).
Follow standard rules of differentiating. You will get
3x^2 + 2y^2 + 4xy*y' = cos(y)*y' (2)
where y' = y'(x) = for brevity.
Collect and combine the terms in formula (2) in order for to have y'
as a factor on one side of the equation
3x^2 + 2y^2 = cos(y)*y' - 4xy*y' ,
3x^2 + 2y^2 = (cos(y) - 4xy)*y' .
Now express y'
y' = . ANSWER
It is the formula which you want to get.