Lesson Find the derivative for a function satisfying given functional equation

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Find the derivative for a function satisfying given functional equation


Problem 1

Find the derivative for function  y = y(x),  satisfying this functional equation   x%5E3%2B2xy%5E2 = sin%28y%29.

Solution

Starting equation is

    x^3 + 2xy^2 = sin(y).    (1)


Here x is an independent variable and y as a function of x 

    y = y(x).


Differentiate the given equation (1) (both sides separately).  
Follow standard rules of differentiating. You will get


    3x^2 + 2y^2 + 4xy*y' = cos(y)*y'    (2)


where y' = y'(x) = %28dy%29%2F%28dx%29 for brevity.


Collect and combine the terms in formula (2) in order for to have y' 
as a factor on one side of the equation


    3x^2 + 2y^2 = cos(y)*y' - 4xy*y' ,

    3x^2 + 2y^2 = (cos(y) - 4xy)*y' .


Now express y'


    y' = %283x%5E2+%2B+2y%5E2%29%2F%28cos%28y%29-4xy%29.    ANSWER


It is the formula which you want to get.


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