Lesson Digit Word Problems
Algebra
->
Customizable Word Problem Solvers
->
Misc
-> Lesson Digit Word Problems
Log On
Ad:
Over 600 Algebra Word Problems at edhelper.com
Word Problems: Miscellaneous Word Problems
Word
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Source code of 'Digit Word Problems'
This Lesson (Digit Word Problems)
was created by by
emargo19(101)
:
View Source
,
Show
About emargo19
:
In a 2-Digit number, the one's digit is 5 less than the 10's digit. If the number is equal to 8 times the sum of its digit, find the number. Let the tens digit be x. Let the ones digit is 5 'less' than 'tens digit'--->(x) which means=x-5. If the number is equal to 8 times the sum of its digit. ***Lets break the above phrase and translate it into algebra.**** In this case the number means----> 10(tens digit)+ (units). So the number-----> {{{10(x)+x-5}}} is equal to----> '=' 8 times -----> 8* the sum of its digit (which means just add the digits)----> {{{x+x+5}}} {{{10x+x-5=8*(x+x-5)}}} {{{11x-5=8*(2x-5)}}} {{{11x-5=16x-40}}} {{{-5x=-35}}} {{{x=7}}} The tens digit is 7. The units digit is {{{x-5=7-5=2}}} The number is {{{10(x)+x-5}}} ={{{10(7)+ 2}}} ={{{70+2}}} ={{{72}}} So the number is 72
: View Source, Show