Lesson Digit Word Problems

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This Lesson (Digit Word Problems) was created by by emargo19(101) About Me : View Source, Show
About emargo19:
In a 2-Digit number, the one's digit is 5 less than the 10's digit. If the number is equal to 8 times the sum of its digit, find the number.

Let the tens digit be x.
Let the ones digit is 5 'less' than 'tens digit'--->(x)
which means=x-5.

If the number is equal to 8 times the sum of its digit.
***Lets break the above phrase and translate it into algebra.****
In this case the number means----> 10(tens digit)+ (units).
So the number-----> 10%28x%29%2Bx-5
is equal to----> '='
8 times -----> 8*
the sum of its digit (which means just add the digits)----> x%2Bx%2B5
10x%2Bx-5=8%2A%28x%2Bx-5%29
11x-5=8%2A%282x-5%29
11x-5=16x-40
-5x=-35
x=7

The tens digit is 7.
The units digit is x-5=7-5=2
The number is 10%28x%29%2Bx-5
=10%287%29%2B+2
=70%2B2
=72

So the number is 72


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