Tutors Answer Your Questions about Geometry Word Problems (FREE)
Question 184616: A rectangular piece of cardboaard is 2 units longer than it is wide. From each of its corners a square piece 2 units on a side is cut out. The flaps are then turned up to form an open box that has a volume of 70 cubic units. Find the length and width of the original piece of cardboard.
box volume = length x width x height
volume = 70
width = w
length = 2w (2 times the width)
height = 2
box volume would be 70=(x)(2w)(2)???
this gives me 70=4w^2??? this seems very difficult to work with, can you help me figure this problem out? Thank you.
Click here to see answer by solver91311(24713)  |
Question 185059: Building a ski ramp. Write an inequality in the variable x for the degree measure of the smallest angle of the triangle shown in the figure, given that the degree measure of the smallest angle is at most 30 degrees.
I have no idea how I got the answer but it seems to be x is less than or equal to 30 ... Is this correct? Can someone please explain. I would greatly appreciate your help.
Click here to see answer by solver91311(24713)  |
Question 185188: I have a circular diagramme. I draw the first sector,then the second one, which is 2 times bigger than the fist one ,and so on, to finally divide the whole diagramme. If we double the previous sector 6 times, find the value of the angle at the middle of the inital sector. PLEASEEEEEEEEEEEEEEE HELPPPPPPPPPPPPPPPP PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE HELPPPPPPPPPPPPPPPPPPP''
Click here to see answer by vleith(2983) |
Question 185187: ``I have a circular diagramme. I draw the first sector,then the second one, which is 2 times bigger than the fist one ,and so on, to finally divide the whole diagramme. If we double the previous sector 6 times, find the value of the angle at the middle of the inital sector.
Click here to see answer by solver91311(24713)  |
Question 185243: Can you please help me with this word problem for some reason Im not understanding the concept of figuring these problems.
The lenght of a rectangular picture is 5 inches greater thatn twice the width. If the perimeter is 112 inches, find the dimensions of the frame.
thanks,
Click here to see answer by stanbon(75887) |
Question 185243: Can you please help me with this word problem for some reason Im not understanding the concept of figuring these problems.
The lenght of a rectangular picture is 5 inches greater thatn twice the width. If the perimeter is 112 inches, find the dimensions of the frame.
thanks,
Click here to see answer by ankor@dixie-net.com(22740)  |
Question 185501: The original problem was:
[A photo is 4 inches longer than it is wide. A 3-inch border is placed around the photo making the total area of the photo and border 165 square inches. What are the dimensions of the photo? ]
So the initial question was…what was the dimensions of the photo. Since the total area of the photo AND border was 165 square inches, logically the
Total Area of Border and Photo (R3) = 165 square inches or the sum of the Area of the Border (R2) and Photo (R1).
So if I want to find the area of the photo the equation should read R3 - R1 = R2 since the total area of 165 subtracting the area of the photo should allow us to solve for the border and then substitute for w.
Let w = width of photo and w + 4 = length of photo so that the dimensions will equal (w)(w+4) = R1
The area of the border can be seen as the added areas of smaller rectangles surrounding the photo. So that :
x +4 + 6 (3) Each long rectangle = (3x + 30) x 2
3x (x)(x+4) 3x Each smaller rectangle = (3x) x 2
x + 4 + 6 (3)
Therefore the area of the border is represented by 6x + 60 + 6x or 12x + 60
The whole equation can be seen as:
165 – area of photo = area of border or
165 – (x2 + 4x) = 12x + 60, using addition principle combine like terms
165 – x2 - 4x = 12x + 60 becomes 0 = x2 +16x -105
And this is where I get stuck because I cant find the factors of 16 and 105 that make this equation solvable?
Can you please show me the solution to this problem so that I understand.
Click here to see answer by Earlsdon(6294) |
Question 185893: would you please help me with this problem, i have been racking my brain for two days to figure it out...ok this is how it goes: There is a sailboat which must have a 110 ft mast and a combined mainsain and jibsail area of 3000 sq ft. The design calls for the mainsail to be 60% of the combined sail area,and the jibsail area to be 40%(of course). If the height of the triangular mainsail is 28ft more than twice the length of the boom, find the length of the boom and the height of the mainsail.
I've figured out this much so far... the mainsail=1800sq ft, and the jibsail =1200sq ft. Height=(2(boom)+28sq ft). and i know that the area of a triangle is A=1/2(base)(heigth). that is about it, i've played around with the numbers but haven't gotten it correct yet. Any help you can offer would be tramendous!Thanks
Click here to see answer by scott8148(6628)  |
Question 185893: would you please help me with this problem, i have been racking my brain for two days to figure it out...ok this is how it goes: There is a sailboat which must have a 110 ft mast and a combined mainsain and jibsail area of 3000 sq ft. The design calls for the mainsail to be 60% of the combined sail area,and the jibsail area to be 40%(of course). If the height of the triangular mainsail is 28ft more than twice the length of the boom, find the length of the boom and the height of the mainsail.
I've figured out this much so far... the mainsail=1800sq ft, and the jibsail =1200sq ft. Height=(2(boom)+28sq ft). and i know that the area of a triangle is A=1/2(base)(heigth). that is about it, i've played around with the numbers but haven't gotten it correct yet. Any help you can offer would be tramendous!Thanks
Click here to see answer by ankor@dixie-net.com(22740)  |
Question 186035: Question: Given an isosceles triangle with a smaller base 0f 2, a perimeter of 70, and acute base angles of 60 degrees, find the trapezoid's area.
Work done so far: I know the formula for Area of trapezoid is .
b1 is 2 but I don't know if I draw altitudes for the trapezoid, the altitudes will equal 2 because the altitudes will make a square. I'm not sure on that part.
Click here to see answer by Edwin McCravy(20054)  |
Question 186376: A room is 11 ft. by 17 ft. It needs to be painted. The cealing is 8 ft above the floor. There are two windows in the room, each one is 3 ft. by 4 ft. The door is 2.5 ft. by 6.5 ft. Find the area of the walls and ceiling.One gallon of paint covers 80.88 sq.ft. How many gallons are needed to paint the room? At $19.11 a gallon, what is the cost to paint the room?
* need to know (area of the walls and ceiling)
(number of gallons needed)
(what the cost will be)
Click here to see answer by checkley77(12844) |
Question 187283: A trough is 2 m long, and its ends are triangles with sides of length 1 m, 1 m, and 1.2 m.
a) Find the volume V of the water in the trough as a function of the water level h.
b) If water is pumped into the empty trough at the rate of 6 L/min, find the water level h as a function of the time t after the pumping begins. (1 m^3 = 1000L)
Click here to see answer by solver91311(24713)  |
Question 188229: Thomas is going to make an open top box by cutting equal squares from the four corners of an 11 inch by 14 inch sheet of cardboard and folding up the sides. If the area of the base is to be 80 square inches, then what size squares should be cut from each corner?
Click here to see answer by solver91311(24713)  |
Question 189037: The longitude of a geographic location is measured in the degrees east or west from the prime meridian (o) to the international dateline (180). Quito, Ecuador on the west coast of south america, has a longitude of 78.5 west. Singapore, on the Malay Peninsula in Asia, has a longitude of 104 east. Both cities are very close to the equator (assume they are on the eqautor for this problem). The diameter of the earth at the equator is 7928 miles. What is the shortest distance from Quito to Singapore? explain how you got your answer
Click here to see answer by ankor@dixie-net.com(22740)  |
Question 189142: Q: A photograph measures 2.25 centimeters high and 5 centimeters wide. How high will the photograph be if it is enlarged to 12 centimeters wide?
My answer is 5.625. Is it correct? I got that answer by taking the 2.25 and multiplying it by 2.5. If not, could you provide the answer and steps taken to solve this problem?
Thanks,
Blake
Click here to see answer by Mathtut(3670) |
Question 189077: How many square yards of linoleum are needed for a kitchen floor that measures 10 ft by 12 ft?
A sheet of plastic 120 cm by 76 cm is to be cut for desks tops that measure 60 cm long and 38 cm wide. How many tops can be made from 6 sheets?
Find the area of a square whose perimeter is 7.2 m.
What is the area of a rectangle 8 m long if its perimeter is 30 m?
Thanks!!!
Click here to see answer by feliz1965(151) |
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