Tutors Answer Your Questions about Geometry Word Problems (FREE)
Question 1056967: The question states: The vertices of triangle ABC are A(-5,3), B(2,2) and C(-1,-5). Which of the following is the length of the matrix from vertex B to side AC? I am told to find the mid point by computing as follows: (((-5 + -1)/2), (3+-5)/2). Why do I add -5 to -1 to get -6 instead of finding the distance between them to get -4?
Click here to see answer by ikleyn(52780)  |
Question 1057289: A rancher has 600600 feet of fencing to put around a rectangular field and then subdivide the field into 33 identical smaller rectangular plots by placing two fences parallel to one of the field's shorter sides. Find the dimensions that maximize the enclosed area. Write your answers as fractions reduced to lowest terms.
Click here to see answer by ikleyn(52780)  |
Question 1057381: A triangular garden is enclosed by a fence. A dog is on a 5-m leash tethered to the fence at point P. One corner, B, of the fence is 6.5 m from P and forms a 41 degrees angle, as shown in the diagram. Determine the total length of fence that the dog can reach, to the nearest tenth of a metre, if the dog cannot reach side AC.
Click here to see answer by ikleyn(52780)  |
Question 1057467: Two adjcent walls of a 40 ft by 35 ft office are to be painted the walls are 8 ft high and include no doors or windows.
If each gallon of paint to be used covers 450 square feet how many gallons are needed
Click here to see answer by ikleyn(52780)  |
Question 1057572: A park designer wanted to place a fountain so that it was close to both the slide and the swings. Each unit on the grid represents 100ft. (a)Find the distance from the slide to the fountain. (b)Find the distance from the swings to the fountain. Show your work.
Click here to see answer by ikleyn(52780)  |
Question 1057675: You are told that a triangle has sides that are 7 inches and 4 inches long. You were also told that the sides form an angle that measure 53°. Is there only one triangle that has these given dimensions why or why not.
Click here to see answer by addingup(3677)  |
Question 1057814: A portion of a track for a roller coaster is supported by two beams of different heights. The 40 foot and 30 foot beams are perpendicular to the ground. Steel cables are attached from the top of one beam to the bottom of the other beam. How far off the ground do the cables intersect?
Click here to see answer by ankor@dixie-net.com(22740)  |
Question 1058022: You have a right triangle with hypotenuse 25. One of the legs gets decreased by 8 and other gets increased 4 and we still have a right triangle with hypotenuse 25. What are the lengths of the legs in the new triangle? (If you could tell me how you got your answer that would be helpful.)
Click here to see answer by josgarithmetic(39617) |
Question 1058022: You have a right triangle with hypotenuse 25. One of the legs gets decreased by 8 and other gets increased 4 and we still have a right triangle with hypotenuse 25. What are the lengths of the legs in the new triangle? (If you could tell me how you got your answer that would be helpful.)
Click here to see answer by ikleyn(52780)  |
Question 1058429: A group of mountain climbers are using trigonometry to find the height of a mountain located in the Rockies. From point A, which is due west of the mountain, the angle of elevation to the top is 56 degrees. From point B, which is due east of the mountain, the angle of elevation to the top is 38 degrees. Points A and B are 9.4km apart. Determine the height of the mountain and round to the nearest meter.
This is what I have:
Triangle ABC-- base of triangle is line AB; top point C. Angle of A = 56 degrees, angle of B = 38 degrees, therefore angle C is 86 degrees. (38 + 56 - 180)
Using sine law to find the length of CB (aka "a") c= AB = 9.4km
a/sin A = c/sin C
a/sin(56) = 9.4/sin(86)
a= 9.4 sin(56)/ sin (86)
a= 7.8 km
Now drawing a line from C to AB and calling it h and thus making a right angle triangle I use sine ratio
sin (38)= opposite/hypotenuse
sin (38) = h/7.8
h= 7.8 sin(38)
h= 4.802km or 4802 meters.
Am I correct?
Click here to see answer by solver91311(24713)  |
Question 1058531: A cottage under construction is to be 15.6m wide. The two sides of the roof are to be supported by equal rafters that meet at a 52 degree angle. Determine the length of the rafters to the nearest cm using
a) cosine law
b) sine law
Now, finding the answer with sine law was straightforward. Since sides b and c are equal the angles for B and C are also equal. 180 degrees - 52 degrees = 128/2 = 64 degrees for B and C.
Then use sine law to get a length of 17.8cm for either side.
Now with cosine law I am unsure. I've got three angles and a length....my textbook says I need either three lengths or two lengths and an angle in between them. I attempted anyway and this is what I got, without using the information provided by using sine law:
15.6^2 = x^2 + x^2 - 2(x)(x)cos(52)
243.36 = 2x^2 - 2x^2 cos(52)
And then I'm lost. Someone suggested these next steps:
243.36 = x^2 (2 - 2 cos(52))
x^2 = 243.36/0.769
x^2 = 316.463
x = sq root of 316.463 = 17.789 = 17.8
*Explain to me how that's legit. How did the right side of the equation turn from
2x^2 - 2x^2 cos (52)
into
x^2(2 - 2 cos(52)) ?
Thank You
Click here to see answer by Boreal(15235)  |
Question 1058536: On a day with no wind, a hot-air balloon hovers at a point above a long, straight river. On the west side of the balloon, a sailboat is spotted in the river at an angle of depression of 48 degrees. On the east side, a canoe spots the balloon at an angle of inclination of 29 degrees. The distance between the balloon and the canoe is 650m.
a) What is the height of the balloon?
b) What is the distance between the balloon and the sailboat?
c) What is the distance between the sailboat and the canoe?
My solutions:
Divide triangle BSC into two right angle triangles by drawing a line between angle B (the top) down to the base (line SC) and calling it h and the point where it meets SC as point D. Angle C
is 29 degrees, length BC is 650m, angle S is 48 degrees. Length BS is c.
a) Solving for h (height) sine theta in triangle BCD:
sin(29) = opposite/hypotenuse
sin(29) = h/650
h = 650sin(29)
h = 315.1 meters
b) sin(48) = opposite/hypotenuse in triangle BDS
sin(48) = 315.1/c
c = 315.1/sin(48)
c = 424 meters
c) finding length of SD
tan(48) = 315.1/SD
SD = 315.1/tan(48)
SD = 283.7
finding length DC
tan(29) = 315.1/DC
DC = 315.1/tan(29)
DC = 568.5
283.7 + 568.5 = distance between sailboat and canoe is 852.2 meters.
Am I right?
Click here to see answer by Boreal(15235)  |
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