Tutors Answer Your Questions about Geometry Word Problems (FREE)
Question 1033336: Given that a 50 foot tall amazon women from a science fiction movie (bad sci-fi) is similar to a normal sized woman, determine her weight given that the average woman is 5.5 ft tall and weighs 140 lbs.
Click here to see answer by Theo(13342)  |
Question 1033573: An open box is to be made from a 24 in. by 36 in. piece of cardboard by cutting out squares of equal size from the four corners and bending up the sides. Find the side of the cut out square so as obtain the maximum volume?
Click here to see answer by ikleyn(52778)  |
Question 1034015: Billy likes to go cycling.
His bike has wheels of diameter 85cm.
He has invented a counter for his bike,
which counts the number of revelations the wheel makes.
One day the counter shows 370 revolutions.
How far has billy cycled?
give your answer to the nearest metre.
Click here to see answer by fractalier(6550)  |
Question 1034019: The sculpture consists of four identical prisms. Jane says the surface area of the sculpture is 4 times the surface area of one prism. Which statement about Jane's method is true?
Jane should multiply volumes, not areas.
Jane should also subtract the areas of six hidden surfaces.
Jane should also add the areas of six hidden surfaces.
Jane is correct.
which is the right answer just to see if this website is not fake
Click here to see answer by macston(5194)  |
Question 1034213: Amanda wants to make a rectangular fenced area for her dogs. She wants the area to be 32 square feet with the length of the yard being twice the width. What would it coast amanda to put up fencing for her dogs if the fencing costs $3.00 per foot?.
Click here to see answer by jorel555(1290) |
Question 1034298: Sam has 15 identical rectangular windows in his home. The length of each window is twice the width, and the area of each window is 8 square feet. Sam wants to put weather stripping around the perimeters of all the windows.
If the weather stripping costs $0.25 per foot, how much will he spend?
Click here to see answer by Cromlix(4381)  |
Question 1034252: The area of the bottom of a shoebox can be written as A(x) = 2x^2 - 4 and the height of the shoebox can be written as h(x) = 3x + 2. Write an expression to represent the volume V(x) of the shoebox.
A) V(x) = 6x^3 - 8
B) V(x) = 2x^2 + 3x - 2
C) V(x) = 2x^2 - 12x - 8
D) V(x) = 6x^3 + 4x^2 - 12x - 8
Click here to see answer by Cromlix(4381)  |
Question 1032796: Billy-Bob Hicks missed the UGA game this past week, so he recorded the game using his
handy-dandy DVR. He made sure to stay off Facebook and Twitter because he knew his
friends would be talking about the game. After the game, Billy-Bob recieves a phone call
from Darealist Williams informing him of the outcome of the game. Natually, Billy-Bob is
upset that Darealist thought it necessary to tell him the score and, in his rage, hurls his cell
phone vertically upward from the top of a 96-foot building. The quadratic function
s(t) = -16t2 + 96t + 96 models the phoneʹs height above the ground, s(t), in feet, t seconds
after it was thrown. How many seconds does it take for the phone to hit the ground?
Round to the nearest tenth of a second if necessary.
Click here to see answer by fractalier(6550)  |
Question 1034536: a rectangular parking space has an area of 150 square feet. the length is 3 feet greater than twice the width. find the dimensions of the space rounded to the nearest tenth of a foot.
I got so far as to write L*W=A and realize that L = 2W+3 and then set it up as W(2W+3)=150 but after that I don't know what is the BEST way to approach this problem.
Click here to see answer by jorel555(1290) |
Question 1034536: a rectangular parking space has an area of 150 square feet. the length is 3 feet greater than twice the width. find the dimensions of the space rounded to the nearest tenth of a foot.
I got so far as to write L*W=A and realize that L = 2W+3 and then set it up as W(2W+3)=150 but after that I don't know what is the BEST way to approach this problem.
Click here to see answer by josgarithmetic(39617) |
Question 1034666: Jose owns a square parcel of land on the north side of West-East Road. The property is on the edge of the road between the one- and two-mile markers. The Farm-To-Market(FM) runs perpendicular to the West-East Road and one mile west of the one-mile marker. The cable company wants to run a cable through Jose's property fro, the intersection of the Farm-To-Market(FM) Road and West-East Road. The cable must divide Jose's parcel of land into two parts that are equal in area. Determine the equation of the line that will represent the path of the buried cable. Determine the length of the portion of the cable that runs across Jose's property.
Click here to see answer by addingup(3677)  |
Question 1034667: David and Sandra Jessee are planning to build a ramp so that the front entrance of their home will be wheelchair accessible. The ramp will be 3-feet wide. It will rise 2in. for each foot of length of horizontal distance. Where the ramp meets the porch, the ramp must be 2ft high. To prove stability for the ramp, the Jessees will install a slab of concrete 4in thick and 6in longer and wider tha the ramp. The top of the slab will be level with the ground. The ramp may be constructed of a concrete or pressure-treated lumber. You are to estimate the cost of materials for constructing the slab, the ramp of concrete, and the ramp of pressure-treated lumber.
a) Determine the length of the base of the ramp.
b) Determine the dimensions of the concrete slab on which the will set.
c) Determine the volume of the concrete in cubic yards needed to construct the slab.
d) if ready mix concrete cost $45 per cubic yard, determine the cost of the concrete needed to construct the slab.
Click here to see answer by addingup(3677)  |
Question 1034780: Jessica wants to build a tool shed in her backyard but is only using the area beyond the path running through the yard. How large would the shed be it is triangular-shaped with sides of length 8 feet, 15 feet, and 20 feet
Click here to see answer by josmiceli(19441)  |
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