SOLUTION: The width of a rectangle is ¾ its length. The perimeter of the rectangle becomes 50 cm when the length and width are each increased by 2cm. What is the Area of the rectangle.

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Question 998260: The width of a rectangle is ¾ its length. The perimeter of the rectangle becomes 50 cm when the length and width are each increased by 2cm. What is the Area of the rectangle.
Found 2 solutions by mananth, josgarithmetic:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
let length be x
width = 3x/4
increased by 2 cm
length (x+2)
width = (3x/4 +2)
2(x+2+3x/4 +2) = 50
/2
x+3x/4 +4 = 25
x+3x/4 =21
7x/4 = 21
7x = 4*21
x = 4*21/7
x=12
length = 12 cm
width = 9cm

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
w and L dimensions.
w=%283%2F4%29L

WHEN 2 cm added to each dimension:
2%28w%2B2%29%2B2%28L%2B2%29=50
Substitution,
2%283L%2F4%2B2%29%2B2%28L%2B2%29=50

3L%2F4%2B2%2BL%2B2=25

3L%2B16%2B4L=100

7L=100-16

L=12
.
.
Area of the original or given rectangle, 108 square centimeters.