SOLUTION: Two sides of a triangle are 3ft and 6ft longer then the third side. If the perimeter of the triangle is 36ft find the lenght of each side

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Question 992859: Two sides of a triangle are 3ft and 6ft longer then the third side. If the perimeter of the triangle is 36ft find the lenght of each side
Found 3 solutions by lwsshak3, Alan3354, ikleyn:
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Two sides of a triangle are 3ft and 6ft longer then the third side. If the perimeter of the triangle is 36ft find the lenght of each side
let x= length of3rd side
x+3=2nd side
x+6 =1st side
2(x+3+x+6)=36
4x+18=36
4x=18
x=4.5
x+3=7.5
3rd side=4.5 ft
1st side=7.5 ft
2nd side= 10.5 ft

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
x + x+3 + x+6 = 36
3x + 9 = 36
3x = 27
x = 9
===============
---> 9, 12 & 15
P = 36

Answer by ikleyn(53875) About Me  (Show Source):
You can put this solution on YOUR website!
.
Two sides of a triangle are 3ft and 6ft longer then the third side.
If the perimeter of the triangle is 36ft find the lenght of each side
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        This problem is solved incorrectly in the post by @lwsshak3.
        For correct solution, see what follows in my post.


let x be the length of3rd side
x+3 = 2nd side
x+6 = 1st side

x + (3+x) + (x+6) = 36

3x + 9 = 36
3x = 27
x = 9
3rd side is 9 ft long.
1st side is 9+6 = 15 ft long
2nd side is 9+3 = 12 ft long.

For these side lengths, the triangle inequalities are valid, so such triangle does exist.

Solved correctly for your right teaching/learning.