SOLUTION: An open box is made from a 30 cm by 58 cm piece of tin by cutting a square from each corner and folding up the edges. The area of the resulting base is 348 cm². What is the length

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: An open box is made from a 30 cm by 58 cm piece of tin by cutting a square from each corner and folding up the edges. The area of the resulting base is 348 cm². What is the length       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 990983: An open box is made from a 30 cm by 58 cm piece of tin by cutting a square from each corner and folding up the edges. The area of the resulting base is 348 cm². What is the length of the sides of the squares?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
x, the edge length of the square removed at each corner;
The area of the base is %2830-2x%29%2858-2x%29;
Area of the four sides other than the base, 2x%2830-2x%29%2B2x%2858-2x%29;

The total area is given.
highlight_green%28%2830-2x%29%2858-2x%29%2B2x%2830-2x%29%2B2x%2858-2x%29=348%29
A quadratic equation needing simplification steps and then solve for x.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
An open box is made from a 30 cm by 58 cm piece of tin by cutting a square from each corner and folding up the edges. The area of the resulting base is 348 cm². What is the length of the sides of the squares?
Let one side of one of the square to be cut off, be S
Length of each side of tin needs to be decreased by: 2S cm
We then get: (30 - 2S)(58 - 2S) = 348
1740+-+176S+%2B+4S%5E2+=+348
4S%5E2+-+176S+%2B+1740+-+348+=+0
4S%5E2+-+176S+%2B+1392+=+0
4%28S%5E2+-+44S+%2B+348%29+=+4%280%29
S%5E2+-+44S+%2B+348+=+0
Using the quadratic equation formula, or completing the square, S, or length of a side of one of the squares = highlight_green%2810.3381%29 cm