Question 987420: Ok it goes like this. The perimeter of a triangle is 55. The side Ab is 70% of the side Dc. The side BC is 3 cms more than the side Ab. Calculate the value of the sides.
Found 2 solutions by solver91311, macston:
Answer by solver91311(24713)   (Show Source):
You can put this solution on YOUR website!
You sure have a lot of vertices on your triangle. Let's see you have A, b, D, c, B, and C. Uppercase letters are different from lower case letters, but even if I let that slide, you still have 4 vertices, A, B, C, and D. Repost this problem and take a little more care about how you type it. I suggest that you proofread your submission carefully BEFORE you click "Submit".
John
My calculator said it, I believe it, that settles it
Answer by macston(5194)  (Show Source):
You can put this solution on YOUR website! .
I am adjusting DC to be AC. If this is not correct, re-post your problem.
.
AC=AC
AB=0.7AC
BC=0.7AC+3cm
.
Perimeter=AB+BC+AC
Perimeter=0.7AC+(0.7AC+3cm)+AC
Perimeter=2.4AC+3cm
55cm=2.4AC+3cm
52cm=2.4AC
21.67cm=AC
ANSWER 1:AC=21.67 cm
.
AB=0.7AC=(0.7)(21.67)=15.17cm
ANSWER 2: AB=15.17cm
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BC=0.7AC+3cm=15.17cm+3cm=18.17cm
ANSWER 3: BC=18.17cm
.
CHECK:
Perimeter=55cm
AB+BC+AC=55cm
15.17cm+18.17cm+21.67cm=55cm
55.01cm=55cm
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