SOLUTION: The area of a rectangle is 150 m2. If the length of the rectangle is 5 meters more than its width, what is the perimeter of the rectangle?

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Question 985172: The area of a rectangle is 150 m2. If the length of the rectangle is 5 meters more than its width, what is the perimeter of the rectangle?
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!

Let  w  be the width of the rectangle in meters  (m).
Then,  in accordance with the condition,  the length of the rectangle is  (w + 5) cm.

The area of the rectangle is the product of its dimensions,  i.e.  w*(w+5),  and it is  150 m%5E2,  according to the condition.

It gives you an equation

w*(w+5) = 150,         or

w%5E2 + 5w = 150,       or

w%5E2 + 5w - 150 = 0.

The roots of this quadratic equation are  10  and  -15.  (Apply the quadratic formula (the lesson  Introduction into Quadratic Equations  or
Vieta's theorem  (see the lesson  Solving quadratic equations without quadratic formula  in this site).

Only the root  10  suits as the solution  (the other root is negative).

So,  the width of the rectangle is  10 m.
The length of the rectangle is  10+5 = 15 m.