SOLUTION: What is the number of square units in the area of a triangle whose sides are 5, 6, and 13 squared. Express your answer in simplest form.

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Question 984638: What is the number of square units in the area of a triangle whose sides are 5, 6, and 13 squared. Express your answer in simplest form.
Found 2 solutions by Timnewman, Alan3354:
Answer by Timnewman(323) About Me  (Show Source):
You can put this solution on YOUR website!
Hi,
Use hero's formula as follows
A=sqrt%28%28s%2A%28s-a%29%2A%28s-b%29%2A%28s-c%29%29%29
Where s=%28a%2Bb%2Bc%29%2F2
Now,s=(5+6+13)/2
=24/2
=12
Substitute the above in the formula
A=sqrt%28%2812%29%2A%2812-5%29%2A%2812-6%29%2A%2812-13%29%29
Evaluating the above,
A=6.5i
Note the answer is a complex number.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
What is the number of square units in the area of a triangle whose sides are 5, 6, and 13 squared. Express your answer in simplest form.
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Not clear.
5, 6 and 13^2 can't be a triangle.
Neither can 5, 6 & 13.
Nor 5^2, 6^2 & 13^2