SOLUTION: a diagonal sidewalk across a rectangular courtyard is 130 feet. The courtyard is 50 feet long. What is the other dimension of the lot?

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: a diagonal sidewalk across a rectangular courtyard is 130 feet. The courtyard is 50 feet long. What is the other dimension of the lot?       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 983915: a diagonal sidewalk across a rectangular courtyard is 130 feet. The courtyard is 50 feet long. What is the other dimension of the lot?
Found 2 solutions by josgarithmetic, macston:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
The sidewalk is a hypotenuse (as well as diagonal of a rectangle) for 50 foot courtyard length and unknown courtyard width w.

Pythagorean Theorem Formula. RECTANGLE cut into two congruent right triangles by the diagonal.

w%5E2%2B50%5E2=130%5E2
Solve.

Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
.
A=known dimension=50ft; B=unknown dimension; C=diagonal=130ft
.
A%5E2%2BB%5E2=C%5E2
.
B%5E2=C%5E2-A%5E2
.
B=sqrt%28C%5E2-A%5E2%29
.
B=sqrt%28%28130ft%29%5E2-%2850ft%29%5E2%29
.
B=sqrt%2816900ft%5E2-2500ft%5E2%29
.
B=sqrt%2814400ft%5E2%29
.
B=120ft
.
ANSWER: The unknown dimension is 120 feet.