SOLUTION: Solve the system. x^2+y^2=1 and x+y=-1

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Question 970330: Solve the system. x^2+y^2=1 and x+y=-1
Found 2 solutions by josgarithmetic, Boreal:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
y=-x-1
;
x%5E2%2B%28-x-1%29%5E2=1
x%5E2%2Bx%5E2%2B2x%2B1=1
2x%5E2%2B2x=0
x%5E2%2Bx=0
x%28x%2B1%29=0

x=0 or x=-1.

Resulting points would be (0,-1) and (-1,0).

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
x^2+y^2=1 Domain is [-1,1} Range is [-1,1]
x+y=-1; y=-x-1; y^2=x^2+2x+1
x^2+x^2+2x+1=1
2x^2+2x=0
divide by 2
x^2 + x=0
x(x+1)=0
x=0, -1
Points are (-1.0) and (0.-1)



graph%28300%2C200%2C-3%2C3%2C-3%2C3%2Csqrt%281-x%5E2%29%2C-sqrt%281-x%5E2%29%2C-1-x%29