SOLUTION: a picture has a height that is 4/3 its width. it is to be enlarged so that the ratio of height to width remains the same, but the area is 192 in2. what are the dimensions of the en

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: a picture has a height that is 4/3 its width. it is to be enlarged so that the ratio of height to width remains the same, but the area is 192 in2. what are the dimensions of the en      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 957148: a picture has a height that is 4/3 its width. it is to be enlarged so that the ratio of height to width remains the same, but the area is 192 in2. what are the dimensions of the enlargement?
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
W=width; L=height=(4/3)W; A=area =192 sq in
A=LW Substitute for L
A=%284%2F3%29%28W%29%28W%29
192in%5E2=%284%2F3%29W%5E2 Multiply each side by 3/4.
144in%5E2=W%5E2 Find the square root of each side.
12in=W ANSWER 1: The width will be 12 inches.
L=%284%2F3%29W=%284%2F3%2912in=16in ANSWER 2: The height will be 16 inches.
CHECK:
A=LW
192in%5E2=%2816in%29%2812in%29
192in%5E2=192in%5E2