SOLUTION: Please help me with this problem:The floor of a cabin is shaped like a rectangle. It has a surface area of 288 square feet. If the perimeter of the floor is 68 feet, what is the le
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Question 956109: Please help me with this problem:The floor of a cabin is shaped like a rectangle. It has a surface area of 288 square feet. If the perimeter of the floor is 68 feet, what is the length of the floor?
You can put this solution on YOUR website! Please help me with this problem:The floor of a cabin is shaped like a rectangle. It has a surface area of 288 square feet. If the perimeter of the floor is 68 feet, what is the length of the floor?
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P = 2L + 2W = 68
L + W = 34
L*W = 288
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Find a pair of factors of 288 with a sum of 34.
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1*288 NG
2*144 NG
3*96 NG
etc
You can put this solution on YOUR website! L=length;W=width; P=perimeter=68ft; A=area=288 sq ft
A=L*W
L=A/W
P=2(L+W) Substitute for L
68ft=2((A/W)+W) Divide each side by 2
34ft=(288sqft/W)+W Subtract W from each side.
34ft-W=288sqft/W Multiply each side by W Subtract 288 from each side.
Quadratic equation (in our case ) has the following solutons:
For these solutions to exist, the discriminant should not be a negative number.
First, we need to compute the discriminant : .
Discriminant d=4 is greater than zero. That means that there are two solutions: .
Quadratic expression can be factored:
Again, the answer is: 16, 18.
Here's your graph:
The width is 16ft or 18ft and length is the other.
ANSWER: The dimensions are 18 feet by 16 feet.
CHECK:
P=2(L+W)
68ft=2(18ft+16ft)
68ft=2(34ft)
68ft=68ft
A=LW
288 sq ft=(18ft)(16ft)
288 sq ft=288 sq ft