SOLUTION: A satellite in geostationary orbit stays over the same spot on Earth. The satellite completes one orbit in the same time that Earth rotates once about its axis (23.93 hours) . If t

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Question 949291: A satellite in geostationary orbit stays over the same spot on Earth. The satellite completes one orbit in the same time that Earth rotates once about its axis (23.93 hours) . If the satellite's orbit has radius 4.23 X 10 to the 7th power m, calculate the satellite's orbital speed (tangential velocity) in meters per second.
Found 2 solutions by Alan3354, macston:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A satellite in geostationary orbit stays over the same spot on Earth. The satellite completes one orbit in the same time that Earth rotates once about its axis (23.93 hours) . If the satellite's orbit has radius 4.23 X 10 to the 7th power m, calculate the satellite's orbital speed (tangential velocity) in meters per second.
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Do it the same way as the Earth's orbital speed.

Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
The circumference of the orbit is %28pi%29diameter so
Circumference=%28pi%29%288.46%2A10%5E7%29+m
This is the distance traveled in one period (23.93 hrs)
rate=distance/time=%28pi%29%288.46%2A10%5E7%29m%2F23.93hrs=%281.111%2A10%5E7%29+m%2Fhr
%281.111%2A10%5E7%29+m%2Fhr*%281+hr%2F3600+sec%29=3085.14 m/sec ANSWER The orbital speed of the satellite is 3085.14 m/sec.