SOLUTION: Find the length of a rectangular lot with a perimeter of 94 meters if the length is 5 meters more than the width. Remember P=2L+2W L=21m L=26m L=47m L=52m

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Question 948922: Find the length of a rectangular lot with a perimeter of 94 meters if the length is 5 meters more than the width. Remember P=2L+2W

L=21m
L=26m
L=47m
L=52m
Found 2 solutions by Fombitz, Zucchini:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
P=2%28L%2BW%29=94
L%2BW=47
.
.
L=W%2B5
So then,
W%2B5%2BW=47
2W=42
W=21m
Then,
L=21%2B5
L=26m

Answer by Zucchini(70) About Me  (Show Source):
You can put this solution on YOUR website!
Width: x
Length: 5 + x
Now, plug in and solve:
94 = 2(5+x) + 2(x)
94 = 10 + 2x + 2x
94 = 10 + 4x
84 = 4x
21 = x
Width: 21m
Length: 26m
So, the second one from your choices.