SOLUTION: Eric is building an open top box using a piece of cardboard that is twice as long as it is wide. To make the walls of the box, he cuts a one inch square from each corner of the box

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Question 944103: Eric is building an open top box using a piece of cardboard that is twice as long as it is wide. To make the walls of the box, he cuts a one inch square from each corner of the box. If the volume of the box is 144 in2, what were the original dimensions of the cardboard?

Found 2 solutions by stanbon, josgarithmetic:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Eric is building an open top box using a piece of cardboard that is twice as long as it is wide. To make the walls of the box, he cuts a one inch square from each corner of the box. If the volume of the box is 144 in^3
what were the original dimensions of the cardboard?
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Original dimensions:: x and 2x
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New dimensions:: x-2 ; 2x-2 ; x
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Equations:
x(x-2)(2(x-1) = 144
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2x(x^2-3x+1) = 144
x^3 - 3x^2 + x - 72 = 0
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x = 5.34
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Cheers,
Stan H.
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Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Dimensions will be w and 2w, as variables.

Forming the open box, the volume is %28w-2%2A1%29%282w-2%2A1%29w=144;
%28w-2%29%282w-2%29w=144
%282w%5E2-2w-4w%2B4%29w-144=0
2w%5E3-6w%5E2%2B4w-144=0
highlight_green%28w%5E3-3w%5E2%2B2w-72=0%29

You would next make of list of possible rational roots to check, and use synthetic division to find which root will work.

Instead of actually doing that, I am using the graphing feature of google.com to inspect the graph of the function for roots or zeros. (Replacement of w with x is necessary there.)

The root may be irrational, appearing to be extremely near to 5.24.
Maybe 5.24028...