SOLUTION: Here is the problem I am having trouble with:The length of a rectangle is 2 cm more than 5 times its width. If the area of the rectangle is 65 cm2, find the dimensions of the rect

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: Here is the problem I am having trouble with:The length of a rectangle is 2 cm more than 5 times its width. If the area of the rectangle is 65 cm2, find the dimensions of the rect      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 94370This question is from textbook
: Here is the problem I am having trouble with:The length of a rectangle is 2 cm more than 5 times its width. If the area of the rectangle is 65 cm2, find the dimensions of the rectangle to the nearest thousandth.I know the width will be x and the length will be 5x+2 but I'm not sure how to proceed. Can you help? Thanks This question is from textbook

Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
You made a good start.
A=L*W 65=x(5x+2)
5x%5E2%2B2x-65=0
Using the quadratic formula x=3.411(width)
5x+2=19.056 (length)
You've got talent. Keep plugging at it.
Ed Jones