SOLUTION: The perimeter of a triangular lot is 117m. The lengths of two sides are each 4/5 of the length of the third side. Find the length of each side.

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Question 941562: The perimeter of a triangular lot is 117m. The lengths of two sides are each 4/5 of the length of the third side. Find the length of each side.
Answer by srinivas.g(540) About Me  (Show Source):
You can put this solution on YOUR website!
let x be the length of e third side
length of other two sides = 4/5 ox x
= 4x/5
perimeter (sum of length of all sides) = 117
%284x%2F5%29%2B%284x%2F5%29+%2Bx=+117
%284x%2F5+%29%2B%284x%2F5%29%2B%285x%2F5%29+=117
%284x%2B4x%2B5x%29%2F5x+=117
+13x%2F5+=117
multiply with 5 on both sides
{{ (13x/5)*5 =117*5}}}
+13x++=+585+
divide with 13 on both sides
+13x%2F13+=585%2F13
+x=45
length of third side(x) = 45
lengths of other two sides = +%284%2F5%29%2A45
= +4%2A9
= 36
Result : lengths of all three sides as follows 36,36,45