SOLUTION: edwin bends a 48 inch wire to form a recatangle. If the width of the rectangle measures 2 times its length, what is the length of the wire

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Question 938434: edwin bends a 48 inch wire to form a recatangle. If the width of the rectangle measures 2 times its length, what is the length of the wire
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

     .

2L + 2w = 48in

L + w = 24in  w+=+2L

L + 2L - 24in

3L = 24in

L = 8in  and w = 16in 2%2A8in

And...checking

2L + 2w = 48in