SOLUTION: Find three consecutive odd intergers such that twice the sum of the first and third more than the second by fifteen

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Question 934955: Find three consecutive odd intergers such that twice the sum of the first and third more than the second by fifteen
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
You need to make your question clearer. Best guessing is you want this:
...such that twice the sum of the first and third is more than the second by fifteen.

The integers: 2n+1, 2n+3, 2n+5.

2%282n%2B1%2B2n%2B5%29-%282n%2B3%29=15
Solve....

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Find three consecutive odd intergers such that twice the sum of the first and third more than the second by fifteen

Let first integer be F
The 2nd and 3rd are: F + 2, and F + 4, respectively
Then: 2(F + F + 4) = F + 2 + 15
2(2F + 4) = F + 17
4F + 8 = F + 17
4F - F = 17 - 8
3F = 9
F, or 1st = 9%2F3, or highlight_green%283%29
2nd integer: 3 + 2, or highlight_green%285%29
3rd integer: 3 + 4, or highlight_green%287%29