SOLUTION: A window in the shape of a rectangle surmounted by an isosceles triangle is to have a width of 75cm and a total height of 180cm. If the total area of the window is to be 12,000cm^2
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Question 9311: A window in the shape of a rectangle surmounted by an isosceles triangle is to have a width of 75cm and a total height of 180cm. If the total area of the window is to be 12,000cm^2, what should be the altitude of the triangle? Answer by rapaljer(4671) (Show Source):
You can put this solution on YOUR website! Since this is a triangle on top of a rectangle, where the total height of the window is 180, let x = height of the triangle, and 180 - x = height (or length) of the rectangle, where 75 is the base of the triangle and the width of the rectangle.
Total area = area triangle + area rectangle
Total area = bh/2 + WL
12000 = (75*x)/2 + (75)(180-x)
Multiply both sides by 2 to clear the fraction:
24000 = 75x + 150(180-x)
24000 = 75x + 27000 - 150x
24000 = -75x + 27000
