SOLUTION: David is making a model of a rectangular solid from a piece of wire 52 inches long. The length is to be twice the width, and the height is to be 1 more inch than the width. What ar

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: David is making a model of a rectangular solid from a piece of wire 52 inches long. The length is to be twice the width, and the height is to be 1 more inch than the width. What ar      Log On

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Question 930446: David is making a model of a rectangular solid from a piece of wire 52 inches long. The length is to be twice the width, and the height is to be 1 more inch than the width. What are the dimensions of the solid?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Hint: the system of equations you need to solve is

system%284%28L%2BW%2BH%29+=+52%2CL+=+2W%2CH=W%2B1%29

You can do two substitutions to go from 4%28L%2BW%2BH%29+=+52 to 4%282W%2BW%2BW%2B1%29+=+52. Solve that for W and use that to find L and H.