SOLUTION: The square root of the sum of 2 consecutive odd integers is 1 less than 3 times the smaller integer. Find the integers..Pls help.thanks a lot.

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: The square root of the sum of 2 consecutive odd integers is 1 less than 3 times the smaller integer. Find the integers..Pls help.thanks a lot.       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 921690: The square root of the sum of 2 consecutive odd integers is 1 less than 3 times the smaller integer. Find the integers..Pls help.thanks a lot.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The square root of the sum of 2 consecutive odd integers is 1 less than 3 times the smaller integer. Find the integers
------------
sqrt%28n+%2B+n%2B2%29+%2B+1+=+3n
sqrt%282n%2B2%29+=+3n-1
Square both sides
2n%2B2+=+9n%5E2+-+6n+%2B+1
Now it's a quadratic
9n%5E2+-+8n+-+1+=+0
(9n + 1)*(n - 1) = 0
n = 1
-------