SOLUTION: The perimeter of a rectangular sandbox is 36 ft. The length is five times the width. a) Write an equation representing the length (𝒍 = 𝒍𝒆𝒏&#119944

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: The perimeter of a rectangular sandbox is 36 ft. The length is five times the width. a) Write an equation representing the length (𝒍 = 𝒍𝒆𝒏&#119944      Log On

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Question 919934: The perimeter of a rectangular sandbox is 36 ft. The length is five times the width.
a) Write an equation representing the length (𝒍 = 𝒍𝒆𝒏𝒈𝒕𝒉)
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
The length: L
the width:W
The perimeter:P=2L%2B2W

if the perimeter of a rectangular sandbox is 36ft,then
2L%2B2W=36ft........eq.1
if the length is five times the width, then
highlight%28L=5W%29........eq.2,=> equation representing the length (𝒍 = 𝒍𝒆𝒏𝒈𝒕𝒉)
if you want to find the length and the width, solve the system:
2L%2B2W=36ft........eq.1
L=5W........eq.2
_________________________
2L%2B2W=36ft........eq.1.....substitute 5W for L
2%2A5W%2B2W=36ft
10W%2B2W=36ft
12W=36ft
W=36ft%2F12
highlight%28W=3ft%29
go to L=5W........eq.2 substitute 3fy for W
L=5%2A3ft
highlight%28L=15ft%29