SOLUTION: two rectangular plots of land are equal in area . the length of the first plot is one and a half times its width. the length of the second plot is 3 meters less than 15 its width.

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Question 918912: two rectangular plots of land are equal in area . the length of the first plot is one and a half times its width. the length of the second plot is 3 meters less than 15 its width.
denoting the width of the first plot by x meters and the width of the second plot by y meters, derive a relation between x and y.

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
x, width of first plot
y, width of second plot

FIRST PLOT
L=x%2F2 and therefore area is %28x%2F2%29x=%281%2F2%29x%5E2.

SECOND PLOT
Length, -3%2B15y and area is %2815y-3%29y.

The areas of the two plots are given as equal:
highlight%28%281%2F2%29x%5E2=%2815y-3%29y%29

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
two rectangular plots of land are equal in area . the length of the first plot is one and a half times its width. the length of the second plot is 3 meters less than 15 its width.
denoting the width of the first plot by x meters and the width of the second plot by y meters, derive a relation between x and y.

With x being the width of the first plot, its length = 1.5x
Area of first plot: x(1.5x) or 1.5x%5E2
With y being the width of the second plot, its length = 15y - 3, assuming
that you meant to write "......3 meters less than 15 times its width."
Area of second plot: y(15y - 3) or 15y%5E2+-+3y
Since their areas are congruent, then it can be said that: highlight_green%28highlight_green%281.5x%5E2+=+15y%5E2+-+3y%29%29