SOLUTION: The perimeter of a rectangle is 56m. If the width were doubled and the length were increased by 25m, the perimeter would be 128m. What are the length and width of the rectangle.

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Question 907900: The perimeter of a rectangle is 56m. If the width were doubled and the length were increased by 25m, the perimeter would be 128m. What are the length and width of the rectangle.

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
w width, L length

2w%2B2L=56, becomes w%2BL=28;

2%282w%29%2B2%28L%2B25%29=128
4w%2B2L%2B50=128
2w%2BL=%28128-50%29%2F2
2w%2BL=39;

highlight%28system%28w%2BL=28%2C2w%2BL=39%29%29
Two linear equations in two unknowns.
Solve the system.