SOLUTION: A piece of wire 42cm long is bent into the shape of a rectangle whose width is twice its length. Find the dimensions of the rectangle

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Question 903914: A piece of wire 42cm long is bent into the shape of a rectangle whose width is twice its length. Find the dimensions of the rectangle
Answer by JulietG(1812) About Me  (Show Source):
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The perimeter of the rectangle is the wire, which is 42cm.
P = 2length + 2width
You're given the width as twice its length.
P = 2L + 2W
P = 42
W = 2L
Substitute the value of W from the bottom equation into the top
P = 2L + 2W
P = 2L + 2(2L)
Distribute
42 = 2L + 4L
42 = 6L
Divide each side by 6
7 = L
If the length is 7, then the width is twice that, or 14
7 + 7 + 14 + 14 = 42