SOLUTION: Ivan has 400 pounds of mixed nuts that contain no peanuts. How many pounds of peanuts should he put into the mixed nuts so that 20% of the mixture is peanuts?
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Question 901844: Ivan has 400 pounds of mixed nuts that contain no peanuts. How many pounds of peanuts should he put into the mixed nuts so that 20% of the mixture is peanuts? Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! x/(400+x)=1/5
5x=400+x
4x=400
x=100
add 100 pounds of peanuts
or
1*y+0*400=0.2(400+y)
1*y+0=80+0.2y
1*y-0.2y=80-0
0.8y=80
y=80/0.8
y=100
