SOLUTION: Suppose the base and height of a triangle sum to 12, and the area of the triangle is 16 square cm. What are the dimensions (base and height) of the triangle?
Please break the pr
Algebra ->
Customizable Word Problem Solvers
-> Geometry
-> SOLUTION: Suppose the base and height of a triangle sum to 12, and the area of the triangle is 16 square cm. What are the dimensions (base and height) of the triangle?
Please break the pr
Log On
Question 900672: Suppose the base and height of a triangle sum to 12, and the area of the triangle is 16 square cm. What are the dimensions (base and height) of the triangle?
Please break the problem down and show me how you solved it,
Thank you!
You can put this solution on YOUR website! let base =b and height =h
(b+h)=12
area of triangle = (1/2) * b*h
(1/2) bh = 16
bh =16*2=32
h= 32/b
Now (b+h)=12
(b+32/b ) = 12
multiply equation by b
b^2+32=12b
b^2-12b+32=0
b^2-8b-4b+32=0
b(b-8)-4(b-8)=0
(b-8)(b-4)=0
b=4 OR 8
if b=4 h=8
if b=8 h= 4
