SOLUTION: The length of the wall is 17m more than its width. If the area of the wall is less than 60m^2, what could be its possible length?

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Question 898976: The length of the wall is 17m more than its width. If the area of the wall is less than 60m^2, what could be its possible length?
Answer by Jc0110(165) About Me  (Show Source):
You can put this solution on YOUR website!
Let y to be the length, while z to be the width.
length, y=z%2B17
width, z=z
Area%3C60m%5E2
y%2Az%3C60
%28z%2B17%29%2Az%3C60
z%5E2%2B17z%3C60
z%5E2%2B17z-60%3C0
%28z%2B20%29%28z-3%29%3C0
The range of z is -20%3Cx%3C3, which holds the number -19,-18,-17,-16,-15,-14,-13,-12,-11,-10,-9,-8,-7,-6,-5,-4,-3,-2,-1,0,1,2.
Since the length for an area cannot be zero and in negatives, the range of z are z%3E0,z%3C3.
To get the possible lengths, substitute z=1 and z=2 into y=z%2B17.
y=1%2B17
y=18
or
y=2%2B17
y=19
Therefore, the possible lengths are 18m and 19m.
**In fact, the value z in range of z%3E0,z%3C3 do not only include 1 and 2, but also involve the positive rational numbers, such as
0.00000...1, 0.001, 0.01, 0.1, 0.2, 0.26, 1.26895, 1.5, 1.55, 1.88888, 2.12, 2.563, 2.889, 2.9, 2.93, 2.99999999.
*As conclusion, value z can be any positive rational numbers as long as it is in this range: z%3E0,z%3C3.