SOLUTION: A man has a lot with a frontage of 26 yds 2 ft. He wishes to set 5 shade trees along the front, equally spaced, one at each end with three between. How far apart will they be?

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: A man has a lot with a frontage of 26 yds 2 ft. He wishes to set 5 shade trees along the front, equally spaced, one at each end with three between. How far apart will they be?      Log On

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Question 897997: A man has a lot with a frontage of 26 yds 2 ft. He wishes to set 5 shade trees along the front, equally spaced, one at each end with three between. How far apart will they be?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
26 yds 2 ft = 78+2=80 feet
So the arrangement will look like,

.
.
.

There are 4 spaces that equal 80 feet.
So the spacing is D=80%2F4=20