SOLUTION: please help with this word problem.
1) A certain rectangle has an area 78 cm^2. If its length is decreased by 3 and its width is increased by 4, it becomes a square. Find the di
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1) A certain rectangle has an area 78 cm^2. If its length is decreased by 3 and its width is increased by 4, it becomes a square. Find the di
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Question 895013: please help with this word problem.
1) A certain rectangle has an area 78 cm^2. If its length is decreased by 3 and its width is increased by 4, it becomes a square. Find the dimension of the original rectangle. Found 2 solutions by reviewermath, lwsshak3:Answer by reviewermath(1029) (Show Source):
You can put this solution on YOUR website! Q:
A certain rectangle has an area 78 cm^2. If its length is decreased by 3 and its width is increased by 4, it becomes a square. Find the dimension of the original rectangle.
A:
Let x = length
therefore, width = 78/x
x - 3 =
Multiply both sides by x
(x - 13)(x + 6) = 0
x = 13 [disregard the negative root]
The length is 13 cm and the width is 6 cm.
You can put this solution on YOUR website! A certain rectangle has an area 78 cm^2. If its length is decreased by 3 and its width is increased by 4, it becomes a square. Find the dimension of the original rectangle.
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let x=length of original rectangle
let y=width of original rectangle
x*y=78
y=78/x
x-3=y+4
x-3=78/x+4
x^2-3x=78+4x
x^2-7x-78=0
(x+6)(x-13)=0
x=-6(reject)
x=13
y=78/13=6
length of original rectangle=13 cm
width of original rectangle=6 cm
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